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1) Anne's father was 35 years of age when she was born while her mother was 32 years old when her brother four years younger to her was born. What is the difference between the ages of her parents?A) 6 B) 7 C) 9 D) 5
Answer & Explanation
Answer: 7 (Mother's age when Anne's brother was born = 32 years.
Father's age when Anne's brother was born = (35 + 4) years = 39 years.
Required difference = (39 - 32) years = 7 years.
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2) The present ages of three John, Ken, Mike are in proportions 5:8:9. Eight years ago, the sum of their ages was 64. Find their present ages (in years).A) 20,32&46 B) 22,32&36 C) 20,32&36 D) 36,32&46
Answer & Explanation
Answer: 20,32&36 (Let their present ages be 5x, 8x and 9x years respectively.
(5x -8)+ (8x -8)+ (9x -8) = 64
22x = 88; x =4.
Their present ages respectively are 20,32&36 respectively )
3) The ratio of Vlad's and Abhi's age is 3: 6.The sum of their age is 90 years. Their ages after 10 years will beA) 45&70 B) 45&75 C) 40&75 D) 40&70
Answer & Explanation
Answer: 40&70 (Let their age be 3x & 6x .
6x + 3x = 90 ; x = 10.
After Ten years their ages will be 40 & 70)
4) In 10 years, A will be twice as old as B was 10 years ago. If A is now 9 years older than B, the present age of B isA) 42 B) 41 C) 39 D) 40
Answer & Explanation
Answer: 39 (Let B's present age be x & A's age is (x+9) ;
x+9+10 =2(x-10);
x = 39. B's present age is 39.)
5) Two years ago a man was 6 times as old as his son. After 18 years, his age will be twice the age of his son. The present age of his son is:A) 7 B) 9 C) 6 D) 5
Answer & Explanation
Answer: 7 (Let son's age 2 years ago be x. Man's age was 6x.
2(x+18 +2 ) = 6x + 2 + 18
x=5. Son's present age is 7 years
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